625x^2-1050x+169=0

Solution for 625x^2-1050x+169=0 equation:

625x^2-1050x+169=0

a = 625; b = -1050; c = +169;
Δ = b2-4ac
Δ = -10502-4·625·169
Δ = 680000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{680000}=\sqrt{40000*17}=\sqrt{40000}*\sqrt{17}=200\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1050)-200\sqrt{17}}{2*625}=\frac{1050-200\sqrt{17}}{1250}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1050)+200\sqrt{17}}{2*625}=\frac{1050+200\sqrt{17}}{1250}
$